{"id":4658,"date":"2026-08-12T16:59:38","date_gmt":"2026-08-12T14:59:38","guid":{"rendered":"https:\/\/ellistat.com\/?post_type=guide-dutilisateur&#038;p=4658"},"modified":"2026-08-12T16:59:38","modified_gmt":"2026-08-12T14:59:38","slug":"valaszfelulet","status":"publish","type":"guide-dutilisateur","link":"https:\/\/ellistat.com\/hu\/guide-dutilisateur\/surface-de-reponse\/","title":{"rendered":"V\u00e1laszfel\u00fclet"},"content":{"rendered":"<p class=\"wp-block-paragraph\">Ez a&nbsp;<strong>teljes kvadratikus modellez\u00e9s<\/strong>&nbsp;: line\u00e1ris hat\u00e1sok, k\u00f6lcs\u00f6nhat\u00e1sok \u00e9s n\u00e9gyzetek. Csak ez a m\u00f3dszer teszi lehet\u0151v\u00e9, hogy az optimumot a tartom\u00e1nyon bel\u00fcl meghat\u00e1rozzuk, \u00e9s helyzet\u00e9t becs\u00fclj\u00fck.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"644\" height=\"416\" src=\"https:\/\/ellistat.com\/wp-content\/uploads\/surface.png\" alt=\"\" class=\"wp-image-4659\" srcset=\"https:\/\/ellistat.com\/wp-content\/uploads\/surface.png 644w, https:\/\/ellistat.com\/wp-content\/uploads\/surface-300x194.png 300w, https:\/\/ellistat.com\/wp-content\/uploads\/surface-18x12.png 18w\" sizes=\"auto, (max-width: 644px) 100vw, 644px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">A t\u00e9nyez\u0151knek a k\u00f6vetkez\u0151knek kell lenni\u00fck:\u00a0<strong>mennyis\u00e9gi<\/strong>, az oldal a \u00abA t\u00e9nyez\u0151knek mennyis\u00e9gi jelleg\u0171eknek kell lenni\u00fck\u00bb \u00fczenetet jelen\u00edti meg, ha egy \u00e9rt\u00e9k nem numerikus, \u00e9s sz\u00e1muk\u00a0<strong>legfeljebb 6<\/strong>. Ezen t\u00falmen\u0151en nincs tov\u00e1bbi t\u00e1bl\u00e1zat.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">1. A rendelkez\u00e9sre \u00e1ll\u00f3 t\u00e1bl\u00e1zatok<\/h2>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><td><strong>T\u00e1bl\u00e1zat<\/strong><\/td><td><strong>Mi is \u0151 val\u00f3j\u00e1ban<\/strong><\/td><td><strong>Min\u0151s\u00e9g<\/strong><\/td><\/tr><\/thead><tbody><tr><td><strong>kompozit<\/strong><\/td><td>K\u00f6z\u00e9pre helyezett \u00f6sszetett \u00e1bra: a faktori\u00e1lis, a csillagpontok, a k\u00f6zponti pontok. A referencia.<\/td><td>*****<\/td><\/tr><tr><td><strong>Behnken-doboz<\/strong><\/td><td>A tartom\u00e1ny \u00e9lek k\u00f6z\u00e9ppontjai. Ker\u00fclje az egyidej\u0171 sz\u00e9ls\u0151s\u00e9ges kombin\u00e1ci\u00f3kat.<\/td><td>***<\/td><\/tr><tr><td><strong>Hoke D1 \/ D4 \/ D6<\/strong><\/td><td>Kev\u00e9s pr\u00f3ba sz\u00e1m\u00e1val j\u00e1r\u00f3 gazdas\u00e1gi tervek.<\/td><td>****<\/td><\/tr><tr><td><strong>A\/B hibrid<\/strong><\/td><td>Rendk\u00edv\u00fcl gazdas\u00e1gos tervek 3 \u00e9s 4 t\u00e9nyez\u0151 eset\u00e9n.<\/td><td>***<\/td><\/tr><tr><td><strong>DSD3 \u2026 DSD8<\/strong><\/td><td>Definitive Screening Designs, amelyet itt modellez\u00e9sre haszn\u00e1lnak.<\/td><td>****<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">A lista a t\u00e9nyez\u0151k sz\u00e1m\u00e1t\u00f3l f\u00fcgg: a kompozit \u00e9s a Hoke-m\u00f3dszer 2 t\u00e9nyez\u0151s; ehhez j\u00f6nnek m\u00e9g a DSD, a hibrid \u00e9s a Box-Behnken m\u00f3dszerek 3, illetve 4 t\u00e9nyez\u0151vel; a Hoke- \u00e9s a Box-Behnken-m\u00f3dszer pedig 5, illetve 6 t\u00e9nyez\u0151vel jelenik meg.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\ud83d\udca1&nbsp;<strong>Ink\u00e1bb Box-Behnken, mint kompozit<\/strong>&nbsp;amikor a sz\u00e9ls\u0151s\u00e9ges kombin\u00e1ci\u00f3k kivitelezhetetlenek vagy vesz\u00e9lyesek: maxim\u00e1lis h\u0151m\u00e9rs\u00e9klet&nbsp;<strong>\u00e9s<\/strong>&nbsp;a maxim\u00e1lis nyom\u00e1s egyszerre. A Box-Behnken-m\u00f3dszer soha nem \u00e9rinti egyszerre k\u00e9t sz\u00e9ls\u0151\u00e9rt\u00e9ket, m\u00edg a kompozit m\u00f3dszer csillagszer\u0171 pontjaival m\u00e9g a kocka (vagy hiperkocka) hat\u00e1rait is t\u00fall\u00e9pi.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">2. A kompozit k\u00e9t be\u00e1ll\u00edt\u00e1sa<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">A kombin\u00e1lt n\u00e9zetben \u2013 \u00e9s kiz\u00e1r\u00f3lag ott \u2013 k\u00e9t be\u00e1ll\u00edt\u00e1s l\u00e1that\u00f3:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>K\u00f6zponti pontok sz\u00e1ma<\/strong>\u00a0; <\/li>\n\n\n\n<li><strong>Kocka\/g\u00f6mb ar\u00e1ny<\/strong>\u00a0(\u03b1): a csillagpontok k\u00f6z\u00f6tti t\u00e1vols\u00e1g, k\u00f3dolt egys\u00e9gekben. Ha \u03b1 = 1, a csillag a kocka oldalain helyezkedik el; ha \u03b1 &gt; 1, a kocka oldalain t\u00fal helyezkedik el.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Az Ellistat kisz\u00e1m\u00edtja \u00e9s&nbsp;<strong>megjelen\u00edti az automatikus \u00e9rt\u00e9keket<\/strong>&nbsp;a mez\u0151k alatt, amelyeket a t\u00e9nyez\u0151k sz\u00e1m\u00e1nak minden v\u00e1ltoz\u00e1sakor \u00fajrasz\u00e1molnak:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><td><strong>T\u00e9nyez\u0151k<\/strong><\/td><td><strong>F\u0151bb pontok<\/strong><\/td><td><strong>Kocka\/g\u00f6mb ar\u00e1ny<\/strong><\/td><\/tr><\/thead><tbody><tr><td>2<\/td><td>5<\/td><td>1,414<\/td><\/tr><tr><td>3<\/td><td>6<\/td><td>1,682<\/td><\/tr><tr><td>4<\/td><td>7<\/td><td>2<\/td><\/tr><tr><td>5<\/td><td>6<\/td><td>2<\/td><\/tr><tr><td>6<\/td><td>9<\/td><td>2,28<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">\u26a0\ufe0f Ezek az \u00e9rt\u00e9kek egy tervet adnak\u00a0<strong>forgat\u00e1s \u00e1ltal izovari\u00e1ns<\/strong>\u00a0: az el\u0151rejelz\u00e9s pontoss\u00e1ga kiz\u00e1r\u00f3lag a k\u00f6z\u00e9ppontt\u00f3l val\u00f3 t\u00e1vols\u00e1gt\u00f3l f\u00fcgg, nem pedig az ir\u00e1nyt\u00f3l. Ezek m\u00f3dos\u00edt\u00e1sa indokolt, k\u00fcl\u00f6n\u00f6sen az \u03b1 \u00e9rt\u00e9k 1-re \u00e1ll\u00edt\u00e1sa, ha a csillagszer\u0171en elhelyezked\u0151 pontok kil\u00e9pn\u00e9nek a fizikailag megval\u00f3s\u00edthat\u00f3 tartom\u00e1nyb\u00f3l; azonban ilyenkor ez a tulajdons\u00e1g elveszik, \u00e9s a pontoss\u00e1g bizonyos ir\u00e1nyokban jobb lesz, mint m\u00e1sokban.<\/p>","protected":false},"featured_media":0,"menu_order":80,"template":"","meta":{"_acf_changed":true},"menu-guide-dutilisateur":[24],"class_list":["post-4658","guide-dutilisateur","type-guide-dutilisateur","status-publish","hentry","menu-guide-dutilisateur-7-doe-plans-dexperiences"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v28.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Surface de r\u00e9ponse - Ellistat<\/title>\n<meta name=\"description\" content=\"Mod\u00e9lisez interactions et courbure, trouvez l&#039;optimum de votre process avec un plan composite, Box-Behnken ou Hoke, adapt\u00e9s \u00e0 vos contraintes de domaine.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/ellistat.com\/hu\/hasznaloi-utmutato\/valaszfelulet\/\" \/>\n<meta property=\"og:locale\" content=\"hu_HU\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Surface de r\u00e9ponse - 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